Question

4. Robbers in a car travelling at 20 m/s pass
a policeman on a motorcycle at rest. The
policeman immediately starts chasing the
robbers. The policeman accelerates at
3 m/s2 for 12 s and thereafter travels at a
constant velocity. Calculate the distance
covered by the policeman before he overtakes

the car​

Answer 1

Answer:

your answer

Explanation:

ANSWER

u=0,t=12sec,α=3m/s

2

Distance covered by police in 12secs

s=ut+1/2at

2

⇒0×12+1/2(3)(12)

2

⇒216m

v=u+at

v=36m/s

Distance travelled by robber in (12+t)sec

Distance =216+36t

Speed × Time=20(12+t)

2.16+36t=240+20t

t=1.5sec

Total time =12+1.5sec=13.5sec

Distance =216+36(1.5)

=216+54

=270m

Answer 2

Answer:   u = 0 ,t = 12 sec ,α = 3m/s  

2

 

Distance covered by police in 12 secs

s = ut + 1/2at 2

 

⇒0×12+1/2(3)(12) 2

 

⇒216m

v=u+at

v=36m/s

Distance travelled by robber in (12+t)sec

Distance =216+36t

Speed × Time=20(12+t)

2.16+36t=240+20t

t=1.5sec

Total time =12+1.5sec=13.5sec

Distance =216+36(1.5)

=216+54

=270m

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