4 root 3 root 2 square
Answers
Answer:
Concept used:
\sqrt[n]{a}=a^{\frac{1}{n}}
n
a
=a
n
1
(a^m)^n=a^{mn}(a
m
)
n
=a
mn
Given:
\sqrt[4]{\sqrt[3]{2^2}}
4
3
2
2
=\sqrt[4]{\sqrt[3]{4}}=
4
3
4
=\sqrt[4]{4^{\frac{1}{3}}}=
4
4
3
1
=({4^{\frac{1}{3}}})^{\frac{1}{4}}=(4
3
1
)
4
1
=4^({\frac{1}{3}.\frac{1}{4}})=4
(
3
1
.
4
1
)
=4^{\frac{1}{3.4}}=4
3.4
1
=4^{\frac{1}{12}}=4
12
1
=(2^2)^{\frac{1}{12}}=(2
2
)
12
1
=2^{\frac{2}{12}}=2
12
2
=2^{\frac{1}{6}}=2
6
1
Answer:
4
3
2
2
=\sqrt[4]{\sqrt[3]{4}}=
4
3
4
=\sqrt[4]{4^{\frac{1}{3}}}=
4
4
3
1
=({4^{\frac{1}{3}}})^{\frac{1}{4}}=(4
3
1
)
4
1
=4^({\frac{1}{3}.\frac{1}{4}})=4
(
3
1
.
4
1
)
=4^{\frac{1}{3.4}}=4
3.4
1
=4^{\frac{1}{12}}=4
12
1
=(2^2)^{\frac{1}{12}}=(2
2
)
12
1
=2^{\frac{2}{12}}=2
12
2
=2^{\frac{1}{6}}=2
6
1