4 root3root 3² equals
![\sqrt[4]{ \sqrt[3]{} 3 {}^{2} }](https://tex.z-dn.net/?f=+%5Csqrt%5B4%5D%7B+%5Csqrt%5B3%5D%7B%7D+3+%7B%7D%5E%7B2%7D+%7D+ "\sqrt[4]{ \sqrt[3]{} 3 {}^{2} }")
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Answer:
4^2= 16
3^2= 9
16+9= 25
16,9 and 25
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