Math, asked by junaid629577, 9 months ago

(4/sec²A)+(1/1+cot²A)+3sin²A=?

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Answered by 217him217
1

Step-by-step explanation:

4/sec²A + (1/1+cot²A) + 3sin²A

= 4cos²A + (1/cosec²A) + 3sin²A

= 4cos²A + sin²A + 3sin²A

= 4 (cos²A + sin²A)

= 4

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