Math, asked by bellu4045, 4 months ago

4. Show that
(a-b) (a+b) + (b-c) (b+c) + (c-a)
(c+a) = 0.
(2 Marks)​

Answers

Answered by GaneshRM2006
1

Answer:

(a-b) (a+b) + (b-c) (b+c) + (c-a)  (c+a) = 0

=(a²-b²)+(b²-c²)+(c²-a²)

=a²-b²+b²-c²+c²-a²

=a²-a²-b²+b²-c²+c²

=0

hence proved

Answered by chotaythesmall
0

the answer is in the photo

Attachments:
Similar questions