Question

4. Show that for fixed mass of nitrogen the masses of oxygen in four oxides of Nitrogen : N20,
NO,NO2,N205 are in the ratio of small integers.

Answer 1

In NO, N2O and NO2, the masses of nitrogen which combine with a fixed mass of oxygen bear a simple ratio of 2: 4: 1.

Answer 2

Answer:

Given,

Mass of the both oxides = 1g each

Mass of Copper in Ist oxide = 0.888 g

Mass of Oxygen in Ist oxide = 1 - 0.888 = 0.112 g

Mass of Copper in IInd oxide = 0.799 g

Mass of Oxygen in IInd oxide = 1 - 0.799 = 0.201 g

In Ist oxide, the amount of oxygen that combines per gram of Cu = (0.112/0.888) = 0.126 g

In IInd oxide, the amount of oxygen that combines per gram of Cu = (0.201/0.799) = 0.251g

Ratio of mass of oxygen in Ist oxide and IInd oxide = 0.126 : 0.251 = 1 : 1.99 = 1 : 2

Thus, the masses of oxygen in the two oxides that combine with a fixed mass of copper is in a whole-number ratio.

Hence, law of multiple proportion is obeyed.

The given data doesn't fit to law of constant proportion.