4. Show that one and only one out of n, n + 4, n + 8, n + 12 and n + 16 is divisible by 5, where n is any positive integer.
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Heya!
Here is yr answer.....
Given,
n, n+4 , n+8 , n+12 , n+16
n is any positive integer......
If n = 1
=> 1 , 1+4, 1+8 , 1+12 , 1+16
=> 1 , 5 , 9 , 12 , 17
Here, 5 only divisible by 5
If n = 2
=> 2 , 2+4 , 2+8 , 2+12 , 2+16
=> 2 , 6 , 10 , 14 , 18
Here, 10 only divisible by 5
If n = 3
=> 3, 3+4 ,3+8 , 3+12 , 3+16
=> 3 , 7 , 11 , 15 , 19
Here, 15 only divisible by 5
By observing... the above values of 'n'
We, can say one and only out of n, n+4, n+8 , n+12 , n+16 is divisible by 5
Hope it hlpz...
Here is yr answer.....
Given,
n, n+4 , n+8 , n+12 , n+16
n is any positive integer......
If n = 1
=> 1 , 1+4, 1+8 , 1+12 , 1+16
=> 1 , 5 , 9 , 12 , 17
Here, 5 only divisible by 5
If n = 2
=> 2 , 2+4 , 2+8 , 2+12 , 2+16
=> 2 , 6 , 10 , 14 , 18
Here, 10 only divisible by 5
If n = 3
=> 3, 3+4 ,3+8 , 3+12 , 3+16
=> 3 , 7 , 11 , 15 , 19
Here, 15 only divisible by 5
By observing... the above values of 'n'
We, can say one and only out of n, n+4, n+8 , n+12 , n+16 is divisible by 5
Hope it hlpz...
Anonymous:
got it??
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