Question

4. Show that the polynomial x³ - 3x² -x+6
has (x-2) as a factors and leaves remainder
3 when it is divided by (x-3). plz give it now​

Answer 1

Answer:

x-2=0

x=2

p(x)= x³-3x²-x+6

p(2)= 2³-3.2²-2+6

=8-12-2+6

= 0

so, (x-2) is the factor of the polynomial x³-3x²-x+6

by factor theorem

if the polynomial x³-3x²-x+6 is. divided by (x-3)

x-3=0

x=3

p(x)= x³-3x²-x+6

p(3)= 3³-3.3²-3+6

=27-27-3+6

=0-3+6

=3

... by remainder theorem ....