Question

4.) show that the value of g is maximum at
the surface of the earth and decreases with
the height or depth​

Answer 1

Answer:

answer for the question is at surface of the earth

Explanation:

Acceleration due to gravity at a height h above the surface g

′

=g(1−

R

2h

)

This suggest that acceleration due to gravity decreases as we go up higher above the earth surface.

At the surface, we have h=0

Thus acceleration due to gravity at the surface g

′

=g (maximum).

Also acceleration due to gravity is zero at the centre of earth.

Thus acceleration due to gravity is maximum at the earth's surface.

Thank you

Answer 2

Answer:

The value of g is maximum at the surface of the earth and decreases with the height or depth​.

Explanation:

The value of 'g' acceleration due to gravity at the surface of Earth is given by:

g = GM/R² = 9.8 m/s²

The value of 'g' acceleration due to gravity at a height 'h' above the ground is:

g' = g (1+h/R)⁻²

The value of g decreases with the increase in height of an object and the value of g becomes zero at an infinite distance from the earth.

The value of 'g' acceleration due to gravity at a depth 'd' below the ground is:
g'' = g (R – d)/R = g(1 - (d/R))

The value of g decreases with the increase in the depth of an object.

Therefore, the value of g is maximum at the surface of the earth and decreases with the height or depth​.

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