4. Show that (x + 4), (x – 3) and (x - 7) are factors of x-6x2 - 19x +84
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Answer:
hope you understand!
Step-by-step explanation:
let f(x)=x3-6x2-19x+84 be the given polynomial
by the factor theorem,
(x+4),(x-3)and (x-7) are the factors of f(x)
if f(-4), f(3) and f(7) are all equal to zero.
therefore,
f(-4)=(-4)3 - 6(4)2 - 19(-4)+84
=-64-96+76+84
=-160+160
=0
also,
f(3)=(3)3 - 6(3)2 - 19(3)+84
=27-54-57+84
=111-111
=0
and,
f(7)=(7)3 - 6(7)2 - 19(7)+84
=243-294-133+84
=427-427
=0
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