4 Si2H3 + 11 O2 ----> 8 SiO2 + 6 H2O
If 15 moles of oxygen react with an excess amount of silicon trihydride, how many moles of water are produced?
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4 parts of Si2H3 react with 11 volumes of oxygen giving 8 parts of SiO2 and 6 parts of H2O.
so, 15 mol is 11 volumes.
Hence, 1 volume is 15/11 mol.
Hence 6 parts of H2O is 15/11 X 6 mol.
8.18 mol
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