Question

4. Simplify this please
VV22 ​

Answer 1

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The Solution is as follows

$\sqrt[4]{ \sqrt[3]{ {2}^{2} } } \\ {2}^{2 \times \frac{1}{3} \times \frac{1}{4} } \\ {2}^{ \frac{1}{3} \times \frac{1}{2} } \\ 2 {}^{ \frac{1}{6} } \\ \sqrt[6]{2}$

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Answer 2

We know that 2 square is 4.

$\sqrt[4]{ \sqrt[3]{ {2}^{2}}} = > \sqrt[4]{ \sqrt[3]{4}} = > \sqrt[4]{ {4}^{ \frac{1}{3}}} = > {4}^{ \frac{1}{3} \times \frac{1}{4}}$

$= > {4}^{ \frac{1}{12}} = > {2}^{ \frac{2}{12}} = > {2}^{ \frac{1}{6}}$

Hope it helps you.