Math, asked by smgmvmo6, 5 hours ago

4. Simplify using DMAS Rule - a. 12 - 15 = 3 + 2 x 4​

Answers

Answered by tsaravanan709
0

Answer:

⇝ Given :-

A car start from rest and acquire a velocity of 72km/h in 20 second.

⇝ To Find :-

Acceleration of the Car.

Distance Traveled By the Car.

⇝ Solution :-

❒ Converting Final Velocity in m/s :

We Have,

\begin{gathered} \text{Final Velocity = 72 km/h} \\ \end{gathered}

Final Velocity = 72 km/h

\begin{gathered} = \bigg(72 \times \frac{5}{18} \bigg) \text{m/s} \\ \end{gathered}

=(72×

18

5

)m/s

\red{:\longmapsto \text{Final Velocity = 20 \: m/s}}:⟼Final Velocity = 20 m/s

Here,

Initial Velocity = u = 0 m/s

Final Velocity = v = 20 m/s

Time Taken = t = 20 s

1 》 Calculating Acceleration :-)

Let Acceleration of Bus be = a m/s².

❒ We Have 1st Equation of Motion as :

\begin{gathered}\large \bf \red \bigstar \: \: \orange{ \underbrace{ \underline{v = u + at}}} \\ \end{gathered}

v=u+at

⏩ Applying 1st Equation of Motion ;

\begin{gathered}:\longmapsto20 = 0 + \text a \times 20 \\ \end{gathered}

:⟼20=0+a×20

\begin{gathered}:\longmapsto20\text a = 20 \\ \end{gathered}

:⟼20a=20

\begin{gathered}:\longmapsto\text a = \cancel \frac{20}{20} \\ \end{gathered}

:⟼a=

20

20

\begin{gathered}\purple{ \Large :\longmapsto \underline {\boxed{{\bf a = 1\:m/s² } }}} \\ \end{gathered}

:⟼

a=1m/s²

Hence,

\large\underline{\pink{\underline{\frak{\pmb{\text Acceleration = 1 \: m/s {}^{2} }}}}}

Acceleration=1m/s

2

Acceleration=1m/s

2

2 》Calculating Distance Traveled :-)

❒ We Have 2nd Equation of Motion as :

\begin{gathered}\large \bf \red \bigstar \: \: \orange{ \underbrace{ \underline{s=ut+\dfrac{1}{2}at^2}}} \\ \end{gathered}

s=ut+

2

1

at

2

⏩ Applying 2nd Equation of Motion

\begin{gathered} :\longmapsto\text{s} = 0 + \frac{1}{2} \times 1 \times {20}^{2} \\ \end{gathered}

:⟼s=0+

2

1

×1×20

2

\begin{gathered}:\longmapsto\text{s} = \cancel\frac{400}{2} \\ \end{gathered}

:⟼s=

2

400

\purple{ \Large :\longmapsto \underline {\boxed{{\bf s = 200 \: m} }}}:⟼

s=200m

Hence,

\large\underline{\pink{\underline{\frak{\pmb{\text Distance \:\text Traveled = 200\: m }}}}}

DistanceTraveled=200m

DistanceTraveled=200m

Answered by ra3968884
0

Answer:



Step-by-step explanation:12 divide 3 + 12 - 5 x 4

Similar questions