Question

4( sin^30° + cos* 60°)-sin? 60° – cos? 45° ) +_ tan 60​

Answer 1

Answer:

4(sin⁴30°cos⁴60°)-2/3(sin²60°-cos²45°)+1/2tan²60°

=4{(1/2)⁴(1/2)⁴}-2/3{(√3/2)²-(1/√2)²}+1/2(√3)²

=4(1/16)(1/16)-2/3(3/4-1/2)+3/2

=1/64-2/3(1/4)+3/2

=1/64+3/2-1/6

=97/64-1/6

=259/192

Step-by-step explanation:

Answer 2

Correct Question :

★ 4(sin⁴30°cos⁴60°) -2/3(sin²60°-cos²45°)+ 1/2tan²60°

→ 4{(1/2)⁴(1/2)⁴}-2/3{(√3/2)²-(1/√2)²}+1/2(√3)²

→ 4(1/16)(1/16)-2/3(3/4-1/2)+3/2

→ 1/64-2/3(1/4)+3/2

→ 1/64+3/2-1/6

→ 97/64 - 1/6

$\longrightarrow\sf \large \dfrac{259}{192}$