4(sin^4 30 + cos^4 60 )-3(cos^2 45 - sin^2 90
Answers
Answered by
23
Hi ,
4(sin⁴ 30° + cos⁴ 60°) - 3(cos² 45° - sin² 90°)
= 4[ (1/2)⁴ + ( 1/2 )⁴ ] - 3[ ( 1/√2 )² - 1² ]
= 4[ 1/16 + 1/16 ] - 3[ 1/2 - 1 ]
= 4 × ( 2/16 ) - 3 ( -1/2 )
= 8/16 + 3/2
= 1/2 + 3/2
= 4/2
= 2
I hope this helps you.
: )
4(sin⁴ 30° + cos⁴ 60°) - 3(cos² 45° - sin² 90°)
= 4[ (1/2)⁴ + ( 1/2 )⁴ ] - 3[ ( 1/√2 )² - 1² ]
= 4[ 1/16 + 1/16 ] - 3[ 1/2 - 1 ]
= 4 × ( 2/16 ) - 3 ( -1/2 )
= 8/16 + 3/2
= 1/2 + 3/2
= 4/2
= 2
I hope this helps you.
: )
Answered by
7
Hiii friend,
Sin 30° = 1/2
Cos60 = 1/2
Cos45° = 1/✓2
and,
Sin90° = 1
Therefore,
4(Sin⁴30° + Cos⁴60°)-3(Cos²45° - Sin²90°)
=> 4{(1/2)⁴ + (1/2)⁴} -3{(1/✓2)² - (1)²}
=> 4(1/16 + 1/16 ) - 3(1/2 -1)
=> 4(1+1/16) - 3(1-2/2)
=> 4 × 2/16 +3/2
=> 2/4 + 3/2
=> 2+6/4
=> 8/4
=> 2
HOPE IT WILL HELP YOU...... :-)
Sin 30° = 1/2
Cos60 = 1/2
Cos45° = 1/✓2
and,
Sin90° = 1
Therefore,
4(Sin⁴30° + Cos⁴60°)-3(Cos²45° - Sin²90°)
=> 4{(1/2)⁴ + (1/2)⁴} -3{(1/✓2)² - (1)²}
=> 4(1/16 + 1/16 ) - 3(1/2 -1)
=> 4(1+1/16) - 3(1-2/2)
=> 4 × 2/16 +3/2
=> 2/4 + 3/2
=> 2+6/4
=> 8/4
=> 2
HOPE IT WILL HELP YOU...... :-)
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