Question

4 (sin 4 30 cos 4 60 )- 3 (cos 2 45 sin 2 90) - 4sin2 45
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Answer 1

Answer:

LHS = `4(sin^4 30°+cos^4 60°)- 3(cos^2 45° – sin^2 90°)`

= `4[(1/2)^4 + (1/2)^4] – 3[(1/sqrt2)^2 + (1)^4]`

= `4[ (1)/(16) + (1)/(16) ] – 3[ (1)/(2) – 1 ] = (4 xx 2 )/(16) + 3 xx (1)/(2) = 2 `

RHS = 2

LHS = RHS

Step-by-step explanation:

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Answer 2

Answer:

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