Math, asked by rajkr21065, 11 months ago

4(sin^4 30°+cos^4 60°)-3(cos^2 45°-sin^2 90°)=4.....proove it????


drashti5: see... instead of √3/2 put there...1/2
drashti5: then 9/16 k badle...1/16...
drashti5: 10/16 k bdle... 2/16
drashti5: 10/4 k bdle... 1/2
drashti5: and.... then... 1/2+3/2
drashti5: = 4/2
drashti5: =2
drashti5: rhs can't be proven...as 4 it will 2...
drashti5: definitely ok!!! i am all correct...
drashti5: if you have any doubt.... please tell ok

Answers

Answered by drashti5
4

4({ \sin}^{4} 30 +  { \cos }^{4} 30) - 3( { \cos }^{2} 45 -  { \sin }^{2} 90) \\  = 4( (\frac{1}{2} )^{4}  +  (\frac{ \sqrt{3} }{2} )^{4} ) - 3( (\frac{1}{ \sqrt{2} } )^{2}   -  {1}^{2} ) \\  = 4( \frac{1}{16}  +  \frac{9}{16} ) - 3( \frac{1}{2}  - 1) \\  = 4( \frac{10}{16} ) - 3( -  \frac{1}{2} ) \\  =  \frac{10}{4}  +  \frac{3}{2}  \\  =  \frac{10 + 6}{4}  \\  =  \frac{16}{4}  \\  = 4
hope this helps..........

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