4 sin(π-π\6)
how to solve
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Answered by
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1divided by2 is the answer for the question
Answered by
2
Hey...friend here is your answer....
=4sin(π-π/6)
=4sin[(6π-π)/6]
=4sin[5π/6]
w.k.t, π =180°
Therefore
=4sin[5(180)/6]
=4sin[900/6]
=4sin[150°]
=4sin(180-30)
w.k.t.sin(180-∅) = sin ∅
and sin30°= 1/2
•°• 4sin30°=4(1/2)
→4/2
→2
=4sin(π-π/6)
=4sin[(6π-π)/6]
=4sin[5π/6]
w.k.t, π =180°
Therefore
=4sin[5(180)/6]
=4sin[900/6]
=4sin[150°]
=4sin(180-30)
w.k.t.sin(180-∅) = sin ∅
and sin30°= 1/2
•°• 4sin30°=4(1/2)
→4/2
→2
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