Question

4 sin π/6 sin² π/3 + 3cos π/3 tan π/4 + cosec² π/2​

Answer 1

Answer:

Prove that: 2sin^2pi/6 + cosec^27pi/6cos^2pi/3 = 3/2

LHS = 2sin^2 pi6 + cosec^2 7pi6cos^2 pi3 = 2sin^2 pi6 + cosec^2 (pi + pi6 ) cos^2 pi3 = 2sin^2 pi6 + cosec^2 ( - pi6 ) cos^2 pi3 ....As theta lies in

Answer 2

Answer:

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