4(sin 60%-os 45°)
tan 30° + cos 90°
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Answer:
Step-by-step explanation:
Given,
4 (sin 60° - cos 45°) tan 30° + cos 90°
= 4 ( √3/2 - 1/√2 ) 1/√3 + 1
= 4 ( √3/2 - 1/√2 × √2/√2 ) 1/√3 + 1
= 4 (√3/2 - √2/2 ) 1/√3 + 1
= 4 ( √3 - √2 / 2 ) 1/ √3 + 1
= Here 4 and 2 are cancelled balance is 2 is multiplying with (√3 - √2 ),we get
= 2 (√3 - √2 ) 1/√3 + 1
= 2√3 -2√2 / √3 + 1
= 2√3 - 2√2 + √3 / √3
= √3 - 2√2 /√3
= √3 / √3 - 2√2 / √3
= 1 - 2√2/√3 is the answer.
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