4 sin A cos cube A - 4 cos A sin cube A is equal to sin 4A
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Answer:
Step-by-step explanation:
R.H.S:
Sin4A = Sin 2(2A)
=> 2Sin2ACos2A
//Sin2A = 2SinACosA
=> 2(2SinACosA)Cos2A
//Cos2A = Cos²A - Sin²A
=> 4SinACosA(Cos²A - Sin²A)
=> 4SinACos³A - 4CosASin³A
=> L.H.S
Hence Proved.
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