4 sin A.sin^2 A +1 - 2 sin^2 A = 2 sin A. Find the value of A
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Answered by
53
see
=> 4 sinA. sin2 A +1 - 2sin2A = 2sin A
=> 4 sinA.sin2 A - 2sin 2A - 2sin A +1 =0
=> 2 sin 2A(2sin A -1) -1( 2sin A -1) =0
=> (2 sin 2A -1) ( 2 sin A -1) =0
now,
=> sinA =1/2, sin2A =1/2.
=> sinA =1/2. (sin 30 =1/2)
=> sin A = sin 30
=> A =30
now,
=> sin 2A =sin 30
=> 2A =30
=> A =15
answer A =15,30
=> 4 sinA. sin2 A +1 - 2sin2A = 2sin A
=> 4 sinA.sin2 A - 2sin 2A - 2sin A +1 =0
=> 2 sin 2A(2sin A -1) -1( 2sin A -1) =0
=> (2 sin 2A -1) ( 2 sin A -1) =0
now,
=> sinA =1/2, sin2A =1/2.
=> sinA =1/2. (sin 30 =1/2)
=> sin A = sin 30
=> A =30
now,
=> sin 2A =sin 30
=> 2A =30
=> A =15
answer A =15,30
dhruvsh:
ohh ok !!!
Answered by
3
Step-by-step explanation:
given
4 Sin A Sin 2A + 1 - 2 Sin 2A = 2 Sin A
4 Sin A 2 Sin A cosA + 1-2 ( 2 sinA cosA) = 2 sin A
8 Sin2 A CosA- 4 SinA cos A =2 Sin A-1
4 Sin A Cos A( 2 Sin A - 1)= 2 Sin A -1
4 sin A cos A=1
2 Sin 2A = 1
Sin24 = 1/2 = Sin 30
2A=30
A=15
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