Math, asked by shaktiprasadnanda07, 5 months ago

4 sin A sin (60° - A) sin (60° + A) - sin 3 A=0​

Answers

Answered by chetanbaviskar72
1

Answer:

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Step-by-step explanation:

Answer:

4sinA. sin(60-A).sin(60+a)-sin3A

Step-by-step explanation:

=4sinA(sin'2 60-sin'2 A)-(3sinA-4sin'3A)

=4sinA(3/4-sin'2A)-3sinA+4sin'3A

=4sinA. 3/4-4sin'3A-3sinA+4sin'3A

=3sinA-3sinA=0 (proved)

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