Math, asked by shivajisatyavan, 11 months ago

4=((sinα))/((sin(85-α))​

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Answered by vikas123456
1

770 Foundations of Trigonometry

10.4 Trigonometric Identities

In Section 10.3, we saw the utility of the Pythagorean Identities in Theorem 10.8 along with the

Quotient and Reciprocal Identities in Theorem 10.6. Not only did these identities help us compute

the values of the circular functions for angles, they were also useful in simplifying expressions

involving the circular functions. In this section, we introduce several collections of identities which

have uses in this course and beyond. Our first set of identities is the ‘Even / Odd’ identities.1

Theorem 10.12. Even / Odd Identities: For all applicable angles θ,

• cos(−θ) = cos(θ)

• sec(−θ) = sec(θ)

• sin(−θ) = − sin(θ)

• csc(−θ) = − csc(θ)

• tan(−θ) = − tan(θ)

• cot(−θ) = − cot(θ)

In light of the Quotient and Reciprocal Identities, Theorem 10.6, it suffices to show cos(−θ) = cos(θ)

and sin(−θ) = − sin(θ). The remaining four circular functions can be expressed in terms of cos(θ)

and sin(θ) so the proofs of their Even / Odd Identities are left as exercises. Consider an angle θ

plotted in standard position. Let θ0 be the angle coterminal with θ with 0 ≤ θ0 < 2π. (We can

construct the angle θ0 by rotating counter-clockwise from the positive x-axis to the terminal side

of θ as pictured below.) Since θ and θ0 are coterminal, cos(θ) = cos(θ0) and sin(θ) = sin(θ0).

x

y

1

1

θ

θ0

x

y

1

1

θ0

−θ0

P(cos(θ0), sin(θ0))

Q(cos(−θ0), sin(−θ0))

We now consider the angles −θ and −θ0. Since θ is coterminal with θ0, there is some integer k so

that θ = θ0 + 2π · k. Therefore, −θ = −θ0 − 2π · k = −θ0 + 2π · (−k). Since k is an integer, so is

(−k), which means −θ is coterminal with −θ0. Hence, cos(−θ) = cos(−θ0) and sin(−θ) = sin(−θ0).

Let P and Q denote the points on the terminal sides of θ0 and −θ0, respectively, which lie on the

Unit Circle. By definition, the coordinates of P are (cos(θ0),sin(θ0)) and the coordinates of Q are

(cos(−θ0),sin(−θ0)). Since θ0 and −θ0 sweep out congruent central sectors of the Unit Circle, it

1As mentioned at the end of Section 10.2, properties of the circular functions when thought of as functions of

angles in radian measure hold equally well if we view these functions as functions of real numbers. Not surprisingly,

the Even / Odd properties of the circular functions are so named because they identify cosine and secant as even

functions, while the remaining four circular functions are odd. (See Section 1.6.)

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