Math, asked by jadavkuldeep777, 8 months ago

4(sin square 30 degree + cos square 60 degree minus 3 cos square 45 degree minus 10 square 45 degree ​

Answers

Answered by alexcube1998
0

Answer:

okay so first correction,

I think your question is meant to be like this:

4( sin^2 30° + cos^2 60° ) - 3( cos^2 45° - tan^2 45° )

so we need to find the values of these standard angles,

sin 30° = 1/2

cos 60° = 1/2

cos 45° = 1/√2

Tan 45° = 1

okay so let's begin,

( simply put the values)

= 4[ ( 1/2)^2 + (1/2)^2 ] - 3[ ( 1/√2)^2 - ( 1 )^2 ]

= 4( 1/4 + 1/4 ) - 3( 1/2 - 1 )

= 4 × 2/4 - 3 × -1/2 ( - × - = + )

= 2 + 3/2

= 7/2

hope it maybe helpful!!

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