4 sin theta = 3 cos theta
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Answered by
5
Answer:
I don'tknow what u mean by the question
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Answered by
0
Answer:
Solution:
⟹4sinθ−3cosθ=0
⟹sinθ=
1−cos
2
θ
⟹4
1−cos
2
θ
−3cosθ=0
⟹4
1−cos
2
θ
=3cosθ
⟹
1−cos
2
θ
=
4
3cosθ
⟹1−cos
2
θ=(
4
3cosθ
)
2
⟹1−cos
2
θ=
16
9cos
2
θ
⟹16(1−cos
2
θ)=9cos
2
θ
⟹16−16cos
2
θ=9cos
2
θ
⟹16=9cos
2
θ+16cos
2
θ
⟹16=25cos
2
θ
⟹cos
2
θ=
25
16
⟹cosθ=
25
16
∴cosθ=
5
4
Now,
⟹sinθ=
1−cos
2
θ
⟹sinθ=
1−(
5
4
)
2
⟹sinθ=
1−
25
16
⟹sinθ=
25
25−16
⟹sinθ=
25
9
∴sinθ=
5
3
⟹sinθ=
5
3
,⟹cosθ=
5
4
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