Question

4 sinA * sin2A + 1 - 2sin2A = 2sinA​

Answer 1

Answer:

Given

4sin Asin 2A +1 -2sin 2A = 2sin A

•4sin A 2sin A Cos A) +1-2(2sin A Cos A) = 2sin A

•8 sin² A Cos A -4sin Acos A=2sin A - 1

•4sin Acos A(2sin A - 1) = 2 sin A-1

•4sin Acos A=1

• 2sin 2A = 1

• sin 24 =1/2 = sin 30

•→2A =30

•A=15

Answer 2

Answer:

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