4. Six years hence a man's age will be three times the age of his son and three years ago he was nine times as old as his son. Find their present ages ten years ago.
Answers
Given : Six years hence a man's age will be three times the age of his son and three years ago he was nine times as old as his son.
To Find :Their present ages [Mistake in the question]
Solution:
Let the ages of a man and his son be x yrs and y yrs.
For Case I :
Six years hence a man's age will be three times the age of his son.
x + 6 = 3(y + 6)
x + 6 = 3y + 18
x = 3y + 18 - 6
x = 3y + 12 ……………..(1)
For Case II :
Three years ago he was nine times as old as his son.
x - 3 = 9(y - 3)
On putting the value of x from equation (1)
3y + 12 - 3 = 9y - 27
3y - 9y = -27 + 3 - 12
-6y = -36
6y = 36
y = 36/6
y = 6
On putting the value of y in equation (1) we get,
x = 3y + 12
x = 3 × 6 + 12
x = 18 + 12
x = 30
Hence, the age of a man and his son are 30 years and 6 years .
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Answer :-
Given : Six years hence a man's age will be three times the age of his son and three years ago he was nine times as old as his son.
To Find :Their present ages [Mistake in the question]
Solution:
Let the ages of a man and his son be x yrs and y yrs.
For Case I :
Six years hence a man's age will be three times the age of his son.
x + 6 = 3(y + 6)
x + 6 = 3y + 18
x = 3y + 18 - 6
x = 3y + 12 ……………..(1)
For Case II :
Three years ago he was nine times as old as his son.
x - 3 = 9(y - 3)
On putting the value of x from equation (1)
3y + 12 - 3 = 9y - 27
3y - 9y = -27 + 3 - 12
-6y = -36
6y = 36
y = 36/6
y = 6
On putting the value of y in equation (1) we get,
x = 3y + 12
x = 3 × 6 + 12
x = 18 + 12
x = 30
Hence, the age of a man and his son are 30 years and 6 years .