Question

4. Solve 3 ydx - 2xdy + x^2
y'(10 ydx - 6xdy) = 0​

Answer 1

Answer:

Step-by-step explanation:

STEPS FOR SOLVING LINEAR EQUATION

3ydx−2xdy+x  

2

y  

−1

(10ydx−6xdy)=0

Combine 3ydx and −2xdy to get ydx.

ydx+x  

2

y  

−1

(10ydx−6xdy)=0

Combine 10ydx and −6xdy to get 4ydx.

ydx+x  

2

y  

−1

×4ydx=0

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

ydx+x  

3

y  

−1

×4yd=0

Reorder the terms.

4×(  

y

1

​  

)dyx  

3

+dxy=0

Multiply both sides of the equation by y.

4×1dyx  

3

+dxyy=0

Multiply y and y to get y  

2

.

4×1dyx  

3

+dxy  

2

=0

Multiply 4 and 1 to get 4.

4dyx  

3

+dxy  

2

=0

Combine all terms containing d.

(4yx  

3

+xy  

2

)d=0

The equation is in standard form.

(xy  

2

+4yx  

3

)d=0

Divide 0 by 4yx  

3

+xy  

2

.

d=0