Question

4. Solve by factorization: 4q2+5q+1=0

Answer 1

Answer:

q ( -1/4 , -1 )

Step-by-step explanation:

4q2 + 5q + 1 = 0

4q2 + 4q + q + 1 = 0

4q ( q + 1 ) + 1 ( q + 1 ) = 0

Now

4q + 1 = 0 q + 1 = 0

4q = _ 1 q = -1

q = -1/4

Answer 2

Given:

An algebraic expression 4q²+5q+1 = 0.

To Find:

The rationalization of the above expression.

Solution:

The given problem can be solved using the concepts of factorization.

1. The given expression is 4q²+5q+1 = 0.

2. The above expression can be also written as,

=> 4q²+5q+1 = 0,

=> 4q²+4q + q +1 = 0,

=> 4q(q+1) + 1(q+1) = 0,

=> (q+1)(4q+1) = 0,

=> q = -1 (OR) q = -1/4.

3. METHOD 2:

=> 4q²+4q + q +1 = 0,

=> 4q²+q +4q +1 = 0,

=> q(4q+4) + 1(4q + 1) = 0,

=> (q+1)(4q+1) = 0,

=> q = -1 (OR) q = -1/4.

Therefore, the values of q are -1/4 and -1.