Question

4.solve for x x² - ( a+b)x + ab=0​

Answer 1

• x²-(a+b)x+ab=0
• x²-ax-bx+ab=0
• x(x-a)-b(x-a)=0
• (x-a)(x-b)=0
• x-a=0 or,x-b=0
• x=a or,x=b

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Answer 2

We have,

x^2 - (a + b)x + ab = 0

or, x^2 - (ax + bx) + ab =  0

or, x^2 - ax - bx + ab = 0

or, x( x-a ) - b( x-a ) = 0

or, (x- b)(x-a) = 0

So, x-b = 0

or, x = b

And, x- a = 0

or, x = a

So, the value of x = a, b.

HOPE THIS WILL HELP YOU.