Question

4) Solve: root 3x²– 11x + 6 root
3 = 0.​

Answer 1

Answer:

√x  

2

+11x+6√3=0

√x  

2

+9x+2x+6√3=0

√x(x+3√3)+2(x+√3)=0

(√3x+2)(x+3√3)=0

either (√3x+2)=0 or (x+3√3)=0

x=−3√3 or −2√3/3

Answer 2

Step-by-step explanation:

√3x²-11x+6√3=0

√3x²-9x-2x+6√3=0

√3x(x-3√3)-2(x-3√3)=0

(x-3√3)(√3x-2)=0

x-3√3=0; √3x-2=0

x=3√3; x=2/√3