Question

4. Solve the equation
3p-4= 2(p-2)
​

Answer 1

Step-by-step explanation:

3p-4=2p-4

3p-2p=-4+4

p=0

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Answer 2

Solution :-

Given :

• $\sf{3p-4= 2(p-2)}$

To Find :

• The value of p.

Now, we are solving equation :

$: \implies{\sf{3p-4=2 (p-2)}}\\ \\ : \implies{\sf {3p-4=2p-4}} \\ \\ : \implies{\sf{3p-2p=-4+4}} \\ \\ : \implies {\boxed{\tt{p=0}}}$.

$\rule {71}{1}$

Procedure used in solving equation :

• We have written 2 (p-2) as 2p-4 because a (b-c) = a×b -c×a.
• We have written 3p-4= 2p-4 as 3p-2p = -4+4 because 2p transposed to LHS and -4 transposed to RHS.

Note : After transposing, a variable or a numeral changes its sign.