Question

4) Solve the equation log↓2(5x+3) = log↓2(2X+1)
for 'x​

Answer 1

Answer:

compare value

=> 5x+3 = 2x+1

=> 5x-2x = 1-3

=> 3x = -2

=> x= -2/3

Answer 2

We have:

$\log _2({5x+3})=\log _2({2x+1})$

⇒ $\log _2({5x+3})-\log _2({2x+1})$ = 0

⇒$\log _2\dfrac{({5x+3})}{2x+1} = \log _21$

⇒ $\dfrac{{5x+3}}{2x+1}$ = 1

⇒ 5x + 3 = 2x + 1

⇒ 5x - 2x = 1 - 3

⇒ 3x = - 2

⇒ x = $\dfrac{-2}{3}$

∴ x = $\dfrac{-2}{3}$