Question

4. Solve the following by the transposition method. a) 6(t - 2) = 18 b) 3/2P-4 = 20 c) 6(x+1)=7(x - 2) d) 2(x+4)-10 = 44 e) 4 - x /6 = 7 6 f) x/2 = -x-2 =​

Answer 1

Answer:

(a) x − 1 = 0

Adding 1 to both sides of the given equation, we obtain

x − 1 + 1 = 0 + 1

x = 1

(b) x + 1 = 0

Subtracting 1 from both sides of the given equation, we obtain

x + 1 − 1 = 0 − 1

x = −1

(c) x − 1 = 5

Adding 1 to both sides of the given equation, we obtain

x − 1 + 1 = 5 + 1

x = 6

(d) x + 6 = 2

Subtracting 6 from both sides of the given equation, we obtain

x + 6 − 6 = 2 − 6

x = −4

(e) y − 4 = −7

Adding 4 to both sides of the given equation, we obtain

y − 4 + 4 = − 7 + 4

y = −3

(f) y − 4 = 4

Adding 4 to both sides of the given equation, we obtain

y − 4 + 4 = 4 + 4

y = 8

(g) y + 4 = 4

Subtracting 4 from both sides of the given equation, we obtain

y + 4 − 4 = 4 − 4

y = 0

(h) y + 4 = −4

Subtracting 4 from both sides of the given equation, we obtain

y + 4 − 4 = − 4 − 4

y = −8