Question

4 Solve using identity:
1 (3x+2y+z)²​

Answer 1

Answer:

1[(3x)²+(2y)²+z²+2(3x×2y)+2(2y×z)+2(3x×z)]

9x²+4y²+z²+2(6xy)+2(2yz)+2(3xz)

9x²+4y²+z²+12xy+4yz+6xz

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