Question

4.
Specific heat of a certain material is 0.2 cal gm-1°C! It value in / kg"! K-1 is
a) 840
b) 940
c) 740
d) 640

​

Answer 1

Answer:

Explanation:

Given, 1 cal =4.2J

So, 0.2calg  

−1

C  

−1

=  

10  

−3

kg×K

0.2×4.2J

​  

=840J/kg.K