Question

4 students from BBA class, 3 students from HRM class and 3 students from accounting class are to be seated in a row. How many sitting arrangements are possible when students of the same class must seat next to each other?

Answer 1

The total number possible sitting arrangements will 5184.

Explanation

There are 4 students from BBA class, 3 students from HRM class and 3 students from accounting class.

Students of the same class must seat next to each other, it means there will be 3 groups of three classes.

So, the possible ways to rearrange 3 groups will be:  $3! = 3*2*1= 6$

Now, we can rearrange the students in their own groups.

So, the number of possible ways to rearrange the students in their own classes will be: $4!*3!*3! = 24*6*6= 864$

Thus, the total number possible sitting arrangements when students of the same class must seat next to each other  $= 864*6 =5184$