Question

4 Sum of the present ages of Manish and Savita is 31. Manish's age 3 years ago
was 4 times the age of Savita. Find their present ages.
​

Answer 1

Savita= 8 yrs

Manish= 31 yrs

Answer:

Here's ur answer

Let the present ages of Manish and Savita be x years and y years respectively.

According to the first condition,

x + y = 31 …(i)

3 years ago,

Manish’s age = (x – 3) years

Savita’s age = (y – 3) years

According to the second condition,

(x – 3) = 4 (y – 3)

∴ x – 3 = 4y – 12

∴ x – 4y = -12 + 3

∴ x – 4y = -9 …(ii)

Subtracting equation (ii) from (i), we get

5y = 40

y= 8

Savita= 8 yr

∴ x = 31 – 8

∴ x = 23

Manish= 31 yr

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Answer 2

✬ Manish's Age = 23 Years ✬

✬ Savita's Age = 5 Years ✬

Step-by-step explanation:

Given:

• Sum of present ages of Manish and Savita is 31.
• 3 years ago Manish's age was 4 times the age of Savita.

To Find:

• Present ages of both ?

Solution: Let the present age of Manish & Savita be x and y years respectively. Therefore,

➟ Manish's + Savita's age = 31

➟ 31 = x + y

➟ 31 – y = xㅤㅤㅤㅤㅤ(i)

[ Three years ago their ages were ]

• Manish's age = (x – 3) years

• Savita's age = (y – 3) years

Now , A/q

• 3 years ago Manish's age was 4 times the age of Savita.

$\implies{\rm }$ (x – 3) = 4(y – 3)

$\implies{\rm }$ 31 – y – 3 = 4y – 12

$\implies{\rm }$ 28 – y = 4y – 12

$\implies{\rm }$ 28 + 12 = 4y + y

$\implies{\rm }$ 40 = 5y

$\implies{\rm }$ 40/5 = y

$\implies{\rm }$ 8 = y

So , the present age of Savita is 8 years and present age of Manish is - 23 years.

➮ x = 31 – y

➮ x = 31 – 8

➮ x = 23 years