Math, asked by tanu4430, 7 months ago


4. Sum of two numbers is 95. If one exceeds the other by 15, find the numbers ​

Answers

Answered by utkarshupadhyay06
1

Answer:

Hello dear,

Step-by-step explanation:

let the first no. be x

so second no. be x-15

now acc to ques,

x + x-15 = 95

2x - 15 = 95

2x = 95 - 15

2x = 80

x = 80/2

x= 40

so, 1st no. = 40

2nd no. = x - 15

= 40 - 15

= 25

I hope it helped you!!

Answered by InfiniteSoul
11

\sf{\bold{\green{\underline{\underline{Given}}}}}

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  • Sum of two no's is 95

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  • One number exceeds other by 15

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\sf{\bold{\green{\underline{\underline{To\:Find}}}}}

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  • Find the numbers = ??

\sf{\bold{\green{\underline{\underline{Solution}}}}}

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Let the 1st no. be x

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Therefore ; second no. = x + 15

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Acc. to the question :-

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x + x + 15 = 95

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2x + 15 = 95

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2x = 95- 15

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2x = 80

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x = 80/ 2

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x = 40

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  • Finding the no.'s

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First no. = x = 40

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Second no. = x + 15 = 40 + 15= 55

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\sf{\bold{\green{\underline{\underline{Answer}}}}}

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  • Required no. = 40 and 55

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\sf{\bold{\green{\underline{\underline{Verification}}}}}

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Sum of 2 no. = 95

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40 + 55 = 95

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95 = 95

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......Hence Verified

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