Question

4. Suppose we represent the distance above the ground by a positive integer and that below the ground by a negative integer then, answer the following:
(1) An elevator descends into a mine shaft at the rate of 6 metres per minute. What will be its position after 30 minutes?
(ii) If it begins to decend from 24 metres above the ground, what will be its position after 80 minutes


​

Answer 1

Answer:

Starting position of mine shaft is = 10m above ground

but,

it moves in opposite direction so it travels the distance (-350 m ) below the ground.

Total distance covered by mine shaft = 10m - (-350m)

= 10 + 350

= 360m

Now, taken to cover a distance of 6m by it = 1 minute

Time taken to cover a distance of 1m by it = \frac{1}{6\ }\min  

6  

1

​  

min

Therefore, tie taken to a cover a distance of 360m = \frac{1}{6}\times\ 360\ =\ 60\ \min\ \  

6

1

​  

× 360 = 60 min  

60 minutes = 1 hour

thus, in one hour the mine shraft reaches = 350 below the ground.

Step-by-step explanation:

brainliest please

Answer 2

Answer:

I am korean and half indian..