Question

4. t3 - 2t2 - 150 ,find the zeroes of this polynomials.​

Answer 1

Step-by-step explanation:

t3 – 2t2 – 15t

= t (t2 – 2t – 15)

= t [t2 – 5t + 3t – 15]

= t [t (t – 5) + 3 (t – 5)]

= t (t + 3) (t – 5)

= (t + 0) (t + 3) (t – 5)

Therefore, the zeroes are 0, (–3) and 5.

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