Question

4 table and 3 chairs chairs together cost rupees 2250 and 3 tables and 4 chairs cost rupees 1950.find the cost of 2 and 1 table

Answer 1

Let the cost of 1 table is rs.x and cost of 1 chair is rs. y.
Then, by the given question,
4x+3y=2250------------(1)
3x+4y=1950------------(2)
Multiplying (1) with 3 and (2) with 4 we get,
12x+9y=6750-----------(3)
12x+16y=7800----------(4)
Now subtracting (4) from (3) we get,

-7y=-1050
or, y=150
Then, x=(1950-4×150)/3=(1950-600)/3=1350/3=450
∴, The total cost of 2 chairs and 1 table is:
2y+x=2×150+450=300+450=750

Answer 2

✴✴$\huge{HEY \: FRIENDS!!}$✴✴

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✴✴$\huge \underline{Here \: is \: your \: answer↓}$⬇⏬⤵

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↪➡$\bf{Let \: the \: cost \: of \: table \: be \: x.}$
↪➡$\bf{and , the \: cost \: of \: chair \: be \: y.}$
▶⏩Now, A/Q.

=> 4 table and 3 chair together cost ₹2250.

$\huge \boxed{4x + 3y = 2250.........(1).}$
▶⏩ Again, 3 tables and 4 chairs together cost ₹1950.

$\huge \boxed{3x + 4y = 1950.........(2).}$

▶⏩Now, multiply equation (1) by 3 and equation (2) by 4. Then , we get.

$\huge \boxed{12x + 9y = 6750.......(3)}$
and,

$\huge \boxed{12x + 16y = 7800.......(4).}$

▶⏩ Now, Substract equation (3) and (4).

12x + 9y = 6750
12x + 16y = 7800
(-).....(-).........(-)
______________
=> -7y = -1050.

$= > y = \frac{ - 1050}{ - 7} .$

$\huge\boxed{y = 150.}$

▶⏩ Put the value of ‘y’ in equation (1).

↪➡4x + 3(150) = 2250.

↪➡4x + 450 = 2250.

↪➡4x = 2250 - 450.

↪➡4x = 1800.

↪➡$x = \frac{1800}{4} .$
↪➡$\huge \boxed{x = 450.}$

✅✅Hence, the cost of one table = ₹450.
and, the cost of one chair = ₹150.✔✔

▶⏩ Now, the cost of two chairs and one table:-)

= 2y + x .

= 2(150) + 450.

= 300 + 450.

= ₹750.✅✔✅✔

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☺☺☺$\huge \underline{Hope \: it \: is \: helpful \: for \: you}$✌✌✌.