Question

4. Taking Ti = 3.14, find the diameters of the circles whose areas are

(ii) 7.065 mm²​

Answer 1

Step-by-step explanation:

$\pi \: r {}^{2} = 7.065$

$3.14 \times r { }^{2} = 7.065$

$r {}^{2} = \frac{7.065}{3.14}$

$r { }^{2} = 2.25$

$r = \sqrt{2.25} = 1.5$

diameter =3 mm