Question

4 tan O= 3,then 4 sin O-cos O/4 sin O + cos O​

Answer 1

Answer:

we know, tan = perpendicular/ base so, after comparing , perpendicular = 3 and base = 4 ∴ hypotenuse = √(3² + 4²) = 5 now, sin ...

Answer 2

Step-by-step explanation:

$4tan \alpha = 3 \\ tan \alpha = \frac{3}{4}$

$\frac{4 \sin( \alpha ) - \cos( \alpha ) }{4 \sin( \alpha + \cos( \alpha ) ) } = \frac{4 \ \frac{ \sin( \alpha ) }{ \cos( \alpha ) } - 1 }{4 \frac{ \sin( \alpha ) }{ \cos( \alpha ) } + 1 } = \frac{4 \tan( \alpha ) - 1 }{4 \tan( \alpha ) + 1 }$

$\frac{4( \frac{3}{4} ) - 1}{4( \frac{3}{4} + 1 } = \frac{3 - 1}{3 + 1} = \frac{2}{4} = \frac{1}{2}$