Question

4. (tan theta+ 2) (2 tan theta + 1) = 5 tan A + sec2 thetha.
state true of false​

Answer 1

Answer:

it is wrong

Step-by-step explanation:

Given Equation is :

= > (tan theta + 2)(2 tan theta + 1)

= > (2tan^2 theta + tantheta + 4tantheta + 2)

= > (2(sec^2theta - 1) + 5tantheta + 2)

= > (2sec^2 theta - 2 + 5tantheta + 2)

= > (2sec^2theta + 5tantheta).

Therefore the final answer will be 2sec^2theta + 5tantheta.

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Answer 2

Answer:

false

Step-by-step explanation:

multiplying LHS u get:

2 tan2 theta +tan theta +4 tan theta+2

2 (tan² theta+1) +5 tan theta

==>>2 sec² theta +5 tan theta

thus LHS ≠ RHS