4 tan theta is equal to 3 find 4 sin theta minus cos theta + 1 by 4 sin theta minus cos theta minus one
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Answered by
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Given,
4 tan = 3
∴ tan = 3/4
As we know,
Tan = Perpendicular / base
Tan = 3/4
Now,
Hypotenuse = √3² + 4² = √9+16 = √25 = 5
Using this, we can find:
Sin = Perpendicular / Hypotenuse = 3/5
Cos = Base / Hypotenuse = 4/5
ATQ,
(4sin - cos + 1)/(4sin + cos - 1)
= (4 × 3/5 - 4/5 + 1)/(4 × 3/5 + 4/5 - 1) [putting values]
= (12 - 4 + 5)/(12 + 4 - 5)
= 13/11
Hope It Helps You! ☺☻☺
Given,
4 tan = 3
∴ tan = 3/4
As we know,
Tan = Perpendicular / base
Tan = 3/4
Now,
Hypotenuse = √3² + 4² = √9+16 = √25 = 5
Using this, we can find:
Sin = Perpendicular / Hypotenuse = 3/5
Cos = Base / Hypotenuse = 4/5
ATQ,
(4sin - cos + 1)/(4sin + cos - 1)
= (4 × 3/5 - 4/5 + 1)/(4 × 3/5 + 4/5 - 1) [putting values]
= (12 - 4 + 5)/(12 + 4 - 5)
= 13/11
Hope It Helps You! ☺☻☺
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1
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