Question

4 tanA=3 then value of sinA-cosA/sinA+cosA
​

Answer 1

Step-by-step explanation:

Angle of projection θ=30

0

initial velocity, μ=15 m/sec

a) Maximum height =

2g

μ

2

sin

2

θ

=

2×9.8

(15)

2

×sin

2

30

0

=2.869 m

b) Time of flight for projectile =

g

2μsinθ

=

9.8

2×15×sin30

0

=1.53 sec

c) Range =

g

μ

2

sin2θ

=

9.8

(15)

2

×sin60

0

=

9.8

225

×

2

3

=19.74 m