Math, asked by Biswajitkumarsamal, 5 months ago


4.Tank A contains 5 times as much water as
Tank B. How much water must be transfer
from Tank A to Tank B so that each tank
contains 45 litres of water?
(A) 30 litres
(B) 60 litres
(C) 75 litres
(D) 45 litres​

Answers

Answered by AadishreePradhan
5

Answer:

Let quantity of water in tank B be x litres.

∴ Quantity of water in the tank A=5x litres

Total water in both the tanks =x+5x

=90 liters

⇒6x=90⇒x=15

∴ Water in tank B=15 litres

⇒ Water in tank A=15×5=75 litres

So, quantity of water to be transferred from tank A to tank B, so that each tank contains 45 litres=75−30=45 litres

Therefore, 30 litres of water should be transferred.

hope it helps

Answered by Pallakavya
2

Answer:

✍ option (A) - 30 litres ✔✔

Step-by-step explanation:

Let quantity of water in tank B be x litres.

∴ Quantity of water in the tank A=5x litres

Total water in both the tanks =x+5x

=90 liters

⇒6x=90⇒x=15

∴ Water in tank B=15 litres

⇒ Water in tank A=15×5=75 litres

So, quantity of water to be transferred from tank A to tank B, so that each tank contains 45 litres=75−30=45 litres.

Therefore, 30 litres of water should be transferred.

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