Question

4 tanx (1-tan2x)
27.Prove that (i) tan 4x =
1-6 tan2x+tanºx
)

Answer 1

Step-by-step explanation:

tan2x= 2tanx/1-tan^2x

tan4x= 2tan2x/1-tan^2 (2x)

= 2(2tanx/1-tan^2 X)/1-(2tanx/1-tan^2x)^2

= 4tanx(1-tan^2x)/1-6tan^2 X + tan^4 x